Lesson Two

Class: Jss1

Subject: Mathematics

Topic: Simple Linear Equations

SubTopic: Equation involving Brackets

Equations involving brackets are equations that contain brackets.

Steps to solve equations with brackets are as follows:

1. A. Open the brackets by:

(I) Multiplying the number in front of the bracket by all the numbers inside the bracket.

Note: If a negative number is in front of a bracket, all the signs inside the brackets change on opening the bracket, but if a positive number is in front of a bracket, all the signs inside the bracket remain the same on opening the bracket.

1. B. Collect like terms
2. C. Divide both sides by the coefficient to get the unknown.

Example 1: Solve the following equations.

(1). 3(a – 2) + 2a = 24  (2).  4(y + 3) = 6(y – 1)  (3).  5(f + 3) – 2(f – 1) = 26

Solution

1. 3(a-2) + 2a =24

Open bracket

3a – 6 + 2a = 24

Collect like terms

3a + 2a = 24 + 6

5a = 30

Divide both sides by 5

5a/5 = 30/5

a = 6

1.  4(y+3)=6(y-1)

Open brackets

4y + 12= 6y – 6

Collect like terms

12 + 6 =6y – 4y

18 = 2y

Divide both sides by 2

18/2 = 2y/2

9 = y

y = 9

1. 5(f + 3) – 2(f – 1) = 26

Open brackets

5f + 15 – 2f + 2 = 26  (Note when a negative number is in front of the bracket)

Collect like terms

5f – 2f = 26 – 15 – 2

3f = 9

Divide both sides by 3

3f/3 = 9/3

f = 3

ASSIGNMENT

Solve the following equations

1. 4(y – 6) – 3y = 25

1. 5(r + 3) – 2(r – 4) = 53

1. 3(k + 1) + 2(k – 3) = 17

To be submitted on Friday 22nd May, 2020 via whatsApp @ 07035773326.

N/B. For further studies, refer to New Concept Mathematics for JSS1 page 166 – 177

## 2 Thoughts to “JSS 1 Mathematics with Assignment”

1. Bernadeth Harrison

Please, what of J’s 2 Mathematics, I can’t find it.

1. allsaintssecschool

go to “blog” keep scrolling. continue with older posts